D(D is correct. The unbalanced reaction can be written out as follows:C8H18 + O2 → CO2 + H2OLet's begin by attempting to balance the carbon atoms, which requires multiplying the CO2 on the right side by 8.C8H18 + O2 → 8 CO2 + H2OUnfortunately, both hydrogen and oxygen are still present in different numbers on each side. Let's save oxygen for last, since it is present in more than one species on the right side. Balance the hydrogen atoms by multiplying the H2O on the right by 9.C8H18 + O2 → 8 CO2 + 9 H2OThis leaves us with 2 oxygen atoms on the left and 25 on the right. We typically prefer whole-number coefficients in front of each species in a reaction, but the only value that 2 can be multiplied by to yield 25 is 12.5.C8H18 + 12.5 O2 → 8 CO2 + 9 H2OTo finish, multiply all species by 2 to remove the decimal, turning 12.5 into 25.2 C8H18 + 25 O2 → 16 CO2 + 18 H2O)

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