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Choose the equation that correctly represents the standard enthalpy of formation for CO if the standard enthalpy of formation for CO is -110.5 kJ/mol.Cgraphite(s) + 1212 O2(g) ⟶ 2 CO(g) ΔΔHo = -110.5 kJCgraphite(s) + CO2(g) ⟶ 2 CO(g) ΔΔHo = -110.5 kJCO(g) ⟶ Cgraphite(s) + O2(g) ΔΔHo = -110.5 kJCgraphite(s) + O(g) ⟶ 2 CO(g) ΔΔHo = -110.5 kJ2 Cgraphite(s) + O2(g) ⟶ 2 CO(g) ΔΔHo = -110.5 kJ

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