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A solution is prepared by dissolving 4.66g of KCl in enough distilled water to give 250 mL of solution. Kcl is a strong electrolyte. How will the freezing point of the solution be different from that of pure water? (Note: Kf for water is 1.86°C/M)A) solution will be 0.930°C lower than pure waterB) solution will be 0.475°C lower than pure waterC) solution will be 0.930°C higher than pure waterD) soluion will be 0.475°C higher than pure water.

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