Genetics Questions

You then sample a second opossum population that has the same starting allele frequency and find that the proportion of A1 homozygotes (A1A1 individuals) is 90%. Assuming that values within 5% of the Hardy-Weinburg expectation are considered at equilibrium, you would likely say thatA.) No evolution is occurring in this population.B.) There might be weak evidence of a process like drift or selection in the second opossum population.C.) There is strong evidence that evolution is occurring in the second opossum population.

If 9% of a human Mediterranean population is born with a severe form of sickle-cell anemia, with homozygous genotype ss, what approximate percentage of the population will be heterozygous Ss for the sickle-cell gene and therefore resistant to malaria? Assume Hardy-Weinberg proportions to answer this question. (Hint: What are your givens, what can you calculate from those givens, what are you trying to find?)A.) 3%B.) 6%C.) 9%D.) 18%E.) 42%

In a short-horned cattle populations, red cattle are homozygous for the red allele, white cattle are homozygous for the white allele, and roan cattle are heterozygotes. Population A consists of 36% red, 16% white, and 48% roan cattle. What are the allele frequencies?A.) red = 0.36, white = 0.16B.) red = 0.6, white = 0.4C.) red = 0.5, white = 0.5D.) Allele frequencies cannot be determined unless the population is in equilibrium.

Hardy-Weinberg equilibrium assumes an extremely large population size because a large population size minimizes the likelihood ofA.) gene flowB.) nonrandom matingC.) natural selectionD.) genetic driftE.) mutations occurring

How can you tell if a population is in HWE? Select all that apply.A. The population is in HWE if p + q = 1B.The population is in HWE if p^2 + 2pq + q^2 = 1C. The population is in HWE if the genotype frequencies are p^2, 2pq, and q^2D. None of these are mathematical indications that a population is in HWE

A mating population contains two alleles, A1 and A2 , with the following frequencies: f( A1) = p = 0.7 and f( A2) = q = 0.3If you observed that the actual genotype frequency of the heterozygote was 0.21, you could concludeA.) that no evolution is occurring in this populationB.) that evolution is occurring in this populationC.) that natural selection is occurring in this populationD.) nothing about whether evolution is occurring; you must first collect more data

If evolution were noticeably occurring in one of these opossum populations, its causes includeA. Mutation onlyB. Mutation and natural selection onlyC. Mutation, natural selection, and genetic driftD. Mutation and gene flow only

What pair of chromosomes are the sex chromosomes?

What process makes a complementary sequence of mRNA

These are in charge if differentiation in eukaryotes

An anticodon has how many bases

When a cell becomes specialized in function it is knows as...

What types of mutation is changing a single base

rRNA helps the ____ construct a protein

What is taken out during editing and what is left behind

What comes first, transcription or translation?

AN insertion or deletion mutation can result in a _____. Which causes all of the amino acids after the mutation change.

Genes contain instructions for building _____.

Type of RNA that carries the amino acid to the Ribosome.

DNA replication results in ____ DNA molecules each with one new strand and one original strand.